. solve the factorise .
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Answer:
3 (t + 1)(10t - 3)
Step-by-step explanation:
• Step 1
(write the equation)
=> 30 t² + 39t - 9
• Step 2
(Express the middle terms coefficient as the sum of two numbers that are the factors of the product of the coefficients of the other terms. )
product of the other terms = 30× 9 = 270
it's factors that sum up to 39 = 30 and 9
=> 30t² + 30t - 9t - 9
Step 3
(taking common)
=> 30t( t + 1) - 9(t + 1)
= (t + 1)(30t - 9)
= (t + 1). 3( 10t - 3)
= 3 (t + 1)(10t - 3)
after factorising we get
3 (t + 1)(10t - 3)
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Hope this helps !
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