Question

solve the first question

Answer 1

Answer:

Step-by-step explanation:

2x^2-x-3 =0

2x^2-3x+2x-3=0

x(2x-3)+1(2x-3)=0

(X+1)(2x-3)=0

Answer 2

apply this formula
$- b \binom{ + }{ - } \sqrt{b {}^{2} } - 4ac \div 2a$
a=2,b=-1,c=-3