Question

solve the first question please

Answer 1

Hello friend, Harish here.

Here is your answer.

$\boxed{\bold{NOTE: Any\ number\ to\ the\ power\ zero\ is \ 1}}$

Then,

⇒ $(3^{-1}+ 4^{-1})^{0} = 1$
__________________________________________________

Hope my answer is helpful to you.

Answer 2

Hey mate !!

Here's your answer !!

Before solving this sum we must know some laws for solving. They are as follows:

Anything to the power -n ( where n is any whole number ) is always turned into positive number by reciprocating it.

$a^{-n} = \frac{1}{ a^{n} }$

Similarly Anything to power 0 is always 1.

$a^{0} = 1$

Now let us solve it:

[tex]= ( 3^{-1} + 4^{-1} )^{0} [/tex]

$= ( \frac{1}{3} + \frac{1}{4} )^{0}$

$= ( \frac{4 + 3}{12} )^{0}$

$= ( \frac{7}{12} )^{0}$

= 1

Hence answer is 1.

Hope my answer helped !!

Cheers !!