solve...............the first term of an ap is 1 and the sum of first 15 terms is 225 find common difference
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a=1
S15=n/2[2a+(n-1)d]
225=15/2[2+14×d]
450=15[2+14d]
450/15=2+14d
30=2+14d
28=14d
d=2
Hope it helps you☺!!!!!!
S15=n/2[2a+(n-1)d]
225=15/2[2+14×d]
450=15[2+14d]
450/15=2+14d
30=2+14d
28=14d
d=2
Hope it helps you☺!!!!!!
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