Solve the folliwing pair of linear equation by substitution method 2x+y=6 and 3x+2y=11
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Answered by
2
Step-by-step explanation:
2x+y=6
=>y=6-2x----(a)
3x+2y=11---(b)
now putting y=6-2x in equation (b) we get
=>3x+2(6-2x)=11
=>3x+12-4x=11
=>12-11=4x-3x
=>1=x
so x=1
Answered by
3
Answer:
2x+y=6 eq. 1st
3x+2y=11 eq. 2nd
2x+y=6
2x=6-y
x=6-y/2
3x+2y=11
3(6-y/2)+2y=11
18-3y/2+2y=11
(18-3y+4y)/2=11
18+y=22
y=22-18
y=4
2x+4=6
2x=6-4
2x=2
x=1
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Step-by-step explanation:
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