Question

Solve the folliwing pair of linear equation by substitution method 2x+y=6 and 3x+2y=11

Answer 1

Step-by-step explanation:

2x+y=6

=>y=6-2x----(a)

3x+2y=11---(b)

now putting y=6-2x in equation (b) we get

=>3x+2(6-2x)=11

=>3x+12-4x=11

=>12-11=4x-3x

=>1=x

so x=1

Answer 2

Answer:

2x+y=6 eq. 1st

3x+2y=11  eq. 2nd

2x+y=6

2x=6-y

x=6-y/2

3x+2y=11

3(6-y/2)+2y=11

18-3y/2+2y=11

(18-3y+4y)/2=11

18+y=22

y=22-18

y=4

2x+4=6

2x=6-4

2x=2

x=1

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Step-by-step explanation: