Question

Solve the following:
1. /a is complementary to /c.
lf /a = 2x – 10 and /c = 4x + 40, find m/a, m/c, and m/b.​

Answer 1

Answer :-

Given :-

• ∠a is complementary to ∠c
• ∠a = 2x - 10
• ∠c = 4x + 40

To Find :-

• ∠a
• ∠b
• ∠c

Solution :-

∠a and ∠c are complementary angles i.e.

∠a + ∠c = 90°

→ 2x - 10 + 4x + 40 = 90°

→ 6x + 30 = 90

→ 6x = 90 - 30

→ x = 60 / 6

→ x = 10

→ ∠a = 2x - 10

→ ∠a = 2 × 10 - 10

→ ∠a = 20 - 10

→ ∠a = 10

Value of ∠a = 10°

→ ∠c = 4x + 40

→ ∠c = 4 × 10 + 40

→ ∠c = 40 + 40

→ ∠c = 80

Value of ∠c = 80°

→ ∠a + ∠b + ∠c = 180°

→ 80 + 10 + ∠b = 180

→ ∠b + 90 = 180

→ ∠b = 90°

Value of ∠b = 90°