Solve the following
1) A moving body travels distance d at uniform speed v1, and travel distance d at uniform speed v2,prove that its
average speed is 2v1v2/2
V + v2
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Answer:
2v₁ v₂ / (v₁ + v₂)
Explanation:
A moving body travels distance d at uniform speed v1, and travel distance d at uniform speed v2,
Distance = d
Uniform speed = v₁
Time = Distance / Speed
=> Time = d/v₁
Distance = d
Uniform speed = v₂
Time = Distance / Speed
=> Time = d/v₂
Total distance = d + d = 2d
Total time = d/v₁ + d/v₂ = d(1/v₁ + 1/v₂)
= d(v₂ + v₁)/(v₁ v₂)
Average speed = Total distance / Total time
= 2d / (d(v₂ + v₁)/(v₁ v₂))
= 2v₁ v₂ / (v₂ + v₁)
= 2v₁ v₂ / (v₁ + v₂)
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