Solve the following 1/ cotA + tanA = sinA X cosA
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1/(cotA +tanA)
=1/[(cosA/sinA) + (sinA/cosA)]
=1/[(cos² +sin²A)/sinAcosA]
=sinAcosA
=1/[(cosA/sinA) + (sinA/cosA)]
=1/[(cos² +sin²A)/sinAcosA]
=sinAcosA
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