Math, asked by Anonymous, 9 months ago

SOLVE THE FOLLOWING

1. Find the difference between the greatest and the smallest number formed using the digits 3, 4, 2, 7, 5.

2. Write the Hindu Arabic numeral for the following

a) XCIX b) LXVI c) XLVI

3. Write the smallest 5-digit number and write the number name of its successor and predecessor.

4. Simplify using BODMAS RULE 8 x (7 – 2) + 3

5. Estimate 4,872 to the nearest tens, hundreds and thousands.

Answers

Answered by spea0r
1

Hi

Here are your answers

A1 The greatest number formed by 3,4,2,7,5 is 75432

The smallest number formed by 3,4,2,7,5 is 23457

Their difference = 75432-23457=51975

A2 a) XCIX=99 b) LXVI= 66 c) XLVI =46

A3 Smallest 5 digit Number = 10000 Successor= 10001 Its number name= Ten thousand One

Its predecessor = 9999 = Nine thousand Nine Hundred Ninety Nine

A4 Bodmas Rule= Brackets of Division Multiplication Addition Subtraction.

Therefore Following This Rule we get 8*(7-2)+3

Solving brackets= 8*5+3

Solving Multiplication= 40+3

Solving Addition=43

We follow Bodmas rule in order starting from Brackets till Subtraction

A5 Number Given=4872

Nearest Tens =4870 as 2 < 5

Nearest Hundreds = 4900 as 72>50

Nearest Thousands = 5000 as 872>500

Hope It helps

If it does Mark as Brainliest ( Please )

Thank You (^-^)

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