Solve the following:-
1) Find the number of 26% of the number is 234.
2) Find your weight if your friend weighs 20% more than you and your friend's weight 20% more than you and your Friend's weight is 48 kg.
3) If cost of 6 soap is Rs.54 find cost of 54 such soaps.
4) Divide Rs.400 between Sanjay and Monu in the ratio of 1.3.
5) In a proportion, the first, third and the fourth terms are 6, 12, &30 respectively. Find the second term.
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Answer:
HOPE IT HELPS pl mark as brainliest
Step-by-step explanation:
1 ) = let no. be x
therefore 26 / 100 X x = 234
ans= 900
2 )let your weight be x
friends weight = 20 % + x
20 % of x = 48
ans= 240
3) = first find cost of 1 soap that = 54 / 6
so, cost of 54 soap = 54 / 6 X 54
ans= 486
sorry dont know answer of 4 & 5
Answered by
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1) let no. Be x
26/100 * x = 234
So, 234*100/26=x
= 23400/26=900
2) friends weight = 48 kg I.e. 20% more than mine weight
My weight = 20/100*48=9.6
48-9.6=38.4kg
3) cost of 6 soaps = 54 rs
Cost of each soap = 54/6= 9 rs
Cost of 54 such soaps = 9*54= 486 rs
4) rs 400 between Sanjay and monu
In the ratio of 1:3
= 1+3=4
Sanjay =1/4*400= 100 rs
Monu = 3/4*400 =300rs
26/100 * x = 234
So, 234*100/26=x
= 23400/26=900
2) friends weight = 48 kg I.e. 20% more than mine weight
My weight = 20/100*48=9.6
48-9.6=38.4kg
3) cost of 6 soaps = 54 rs
Cost of each soap = 54/6= 9 rs
Cost of 54 such soaps = 9*54= 486 rs
4) rs 400 between Sanjay and monu
In the ratio of 1:3
= 1+3=4
Sanjay =1/4*400= 100 rs
Monu = 3/4*400 =300rs
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