Math, asked by Anonymous, 3 months ago

Solve the following:-
1) Find the number of 26% of the number is 234.

2) Find your weight if your friend weighs 20% more than you and your friend's weight 20% more than you and your Friend's weight is 48 kg.

3) If cost of 6 soap is Rs.54 find cost of 54 such soaps.

4) Divide Rs.400 between Sanjay and Monu in the ratio of 1.3.

5) In a proportion, the first, third and the fourth terms are 6, 12, &30 respectively. Find the second term.

Answers

Answered by ELSA398
0

Answer:

HOPE IT  HELPS pl mark as brainliest

Step-by-step explanation:

1 ) =  let no. be x

therefore 26 / 100  X x = 234

ans= 900

2 )let your weight be x

friends weight  = 20 % + x  

20 % of x = 48

ans=  240

3) = first find cost of 1 soap that = 54 / 6

so, cost of 54 soap =  54 / 6   X 54

ans= 486

sorry   dont  know answer of  4 & 5

Answered by sami444492
0
1) let no. Be x
26/100 * x = 234
So, 234*100/26=x
= 23400/26=900
2) friends weight = 48 kg I.e. 20% more than mine weight

My weight = 20/100*48=9.6
48-9.6=38.4kg

3) cost of 6 soaps = 54 rs
Cost of each soap = 54/6= 9 rs
Cost of 54 such soaps = 9*54= 486 rs

4) rs 400 between Sanjay and monu
In the ratio of 1:3
= 1+3=4
Sanjay =1/4*400= 100 rs
Monu = 3/4*400 =300rs

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