Solve the following
1. The gravitational force of 733 Newton acts on Mahendra who has mass of 75 kg starting from rest what will be
Mahendra's Velocity after 1 second if he is falling down due to gravitational force of the earth
Ans:
Answers
Given : The gravitational force of 733 Newton acts on Mahendra who has mass of 75 kg starting from rest
To Find : Velocity after 1 second if he is falling down due to gravitational force of the earth.
Solution:
Gravitational force of 733 Newton
Mass = 75 kg
F = mg
=> 733 = 75g
=> g = 733/75 m/s²
v = u + at
u =0 as start from rest
t = 1 sec
a = g = 733/75
v = 0 + (733/75)×1
v = 9.77 m/s
Velocity after 1 second = 9.77 m/s
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