Question

SOLVE THE FOLLOWING

1)The sum of two numbers is 11 and their difference is 5. Find the numbers.

2) The angles of a triangle are in the ratio 2 : 3 : 4. Find the angles of the triangle.

3)The difference between two positive numbers is 40 and the ratio of these integers is 1 : 3. Find the integers.

Answer 1

Answer:

1. $let \: angles \: of \: triangle \: be \: a \: \: b \: \: c \\ let \: a \: \: b \: c \: \: is \: x \: \\ so \: the \: angles \: are \: 2x + 3x + 4x \\ sum \: sum \: of \: the \: angles \: of \: a \: triangle \: = 180 \\ 2x + 3x + 4x = 180 \\ 9x = 180 \\ x = 20 \\ 2x = 2 \times 20 = 40 = a \\ 3x = 3 \times 20 = 60 = b \\ 4x = 4 \times 20 = 80 = c$
2. $ratio \: of \: two \: positive \: \: numbers \: = x \: and \: 3x \\ 3x - x = 40 \\ 2x = 40 \\ x = \frac{40}{2 } \\ x = 20 \\ x = 20 \\ 3x = 3 \times 20 = 60$

please mark as brainliest

I will do next part