Question

solve the following 1) write 7-4x-x²=0 in the standard form​

Answer 1

Answer:

The standard form of 7 - 4x - x² = 0  is x² + 4x - 7 = 0.

Step-by-step explanation:

Given,

The quadratic equation:

7 - 4x - x² = 0

To find,

The value of 'x' and the standard form of the given quadratic equation.

Calculation,

The standard form of a quadratic equation is:

ax² + bx + c = 0

So in our given quadratic equation:

a = -1, b = -4, c = 7

So the standard form of 7 - 4x - x² = 0 is:

-x² - 4x + 7 = 0

(OR)

x² + 4x - 7 = 0

Therefore, the standard form of 7 - 4x - x² = 0  is x² + 4x - 7 = 0.

#SPJ3

Answer 2

Answer:

, $x^2 + 4x - 7 = 0$ is the standard form $7 - 4x - x^2 = 0$.

Step-by-step explanation:

Explanation:

Given that, $7 - 4x - x^2 = 0$

Here we can see that the highest power of x  is 2.

So, here we conclude that the given equation is quadratic.

• The quadratic equation $x^2 + 4x + 1$ = 0 can be solved for x using any equation that has one term in which the unknown is squared and no terms in which it is raised to a higher power.

• General form of a quadratic equation is $ax^2 + bx + c = 0$.

Now, from the question we have, $7 - 4x - x^2 = 0$

This can be written as,

⇒ $-x^2 - 4x + 7 = 0$

Now, we take "- minus " as common.

⇒ $- (x^2 + 4x - 7)$ = 0

⇒ $x^2 + 4x - 7 = 0$

Final answer:

Hence, $x^2 + 4x - 7 = 0$ is the standard form $7 - 4x - x^2 = 0$.

#SPJ3