solve the following:
2 (3u-v) =5uv
2(u+3v)=5uv
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Step-by-step explanation:
Answer
2(3u−v)=5uv ....(1)
2(u+3v)=5uv ....(2)
From (1) and (2) we get
2(3u−v)=2(u+3v)
⇒3u−v=u+3v
⇒3u−u=3v+v
⇒2u=4v
⇒u=2v
Substitute u=2v in (1) we get
2(3×2v−v)=5×2v×v
⇒6v−v=5×v
2
⇒5v=5×v
2
⇒v=v
2
⇒v
2
−v=0
⇒v(v−1)=0
⇒v=0,v=1
Put v=0 in u=2v⇒u=0
∴u=0,v=0u=2,v=1
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