solve the following: 2. a tree is broken at a height of 4 cm from the ground. its top touches the ground at a distance of 3 cm from the base of the tree. find the original height of the tree.
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Answer:
9 cm
Step-by-step explanation:
by using Pythagoras theorem
- ac^2=ab^2+bc^2
(^2 means spuare)
- ac^2 = (4)^2 + (3)^2
- ac^2 =16 + 9
- ac^2 = 25
- ac = 5
we have find ac = 5 (broken part of tree from 4 cm to ground)
now add 4 + 5 means remaining part + broken part of tree
- 4+5 = 9 cm
so the original height of the tree is 9 cm
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