Solve the following
217x+131y=913
131x+217y=827
Find x and y
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Answered by
3
Answer:
217x+131y=913 (i)
131x+217y=827 (ii)
Adding equations (i) and (ii), we get
348x+348y=1740⇒x+y=5 (iii)
Subtracting equation (ii) from equation (ii), we get
86x−86y=86⇒x−y=1 (iv)
Adding equation (iii) and (iv), we get
2x=6⇒x=3
Putting x=3 in equation(iii), we get y=2
Hence, x=3 and y=2 is the solution of the given system of equations.
Answered by
4
We have,
217x+131y=913 (i)
131x+217y=827 (ii)
Adding equations (i) and (ii), we get
348x+348y=1740⇒x+y=5 (iii)
Subtracting equation (ii) from equation (ii), we get
86x−86y=86⇒x−y=1 (iv)
Adding equation (iii) and (iv), we get
2x=6⇒x=3
Putting x=3 in equation(iii), we get y=2
Hence, x=3 and y=2 is the solution of the given system of equations.
hope it's helps you
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