solve the following
21a²-14a²+42 by 7a²
Answers
Answered by
4
Answer:
The greatest common factor of the terms 28a², 14a²b² and 21a⁴ of the expression
28a² + 14a²b² – 21a⁴ is 7a².
Also, we can write 28a² = 7a². 4, 14a²b² = 7a² . 2b² and 21a⁴ = 7a² . 3a².
Therefore, 28a² + 14a²b² – 21a⁴ = 7a². 4 + 7a² . 2b² – 7a² . 3a²
= 7a² (4 + 2b² – 3a²)
Hope it will help you
Similar questions