Question

solve the following

Answer 1

x=3+√2
x=2+1+√2
x=(√2)^2+1^2+2×1×√2
x=(√2+1)^2
√x=√2+1
(1) √x+1÷√x
(√2+1)+1÷(√2+1)
after rationalizing we get
{√2+1}+(√2-1)÷1
√2+1+√2-1
2√2

(2) √x-1÷√x
(√2+1)-1÷(√2+1)
after rationalizing we get
(√2+1)-(√2-1)÷1
√2+1-√2+1
=2