Question

Solve the following. ​

Answer 1

Given question:

$\frac{8x + 3}{2x - 3} = \frac{4x}{x - 3}$

Solution:

$x - 3(8x + 3) = 2x - 3(4x)$

${8x}^{2} + 3x - 24x - 9 = {8x}^{2} - 12x$

${8x}^{2} - 21x - 9 = {8x}^{2} - 12x$

${8x}^{2} - {8x}^{2} -9 = - 12x + 21x$

$- 9 = 9x$

$\frac{ - 9}{9} = x$

$- 1 = x$

$x = - 1 \: or \: x = 1$

Answer 2

Answer:

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