Question

solve the following
(2a+3b-5c)²​

Answer 1

Answer:

4$a^{2}$+12ab−20ac+9$b^{2}$−30bc+25$c^{2}$

Step-by-step explanation:

(2a+3b−5c$)^{2}$

=(2a+3b+−5c)(2a+3b+−5c)

=(2a)(2a)+(2a)(3b)+(2a)(−5c)+(3b)(2a)+(3b)(3b)+(3b)(−5c)+(−5c)(2a)+(−5c)(3b)+(−5c)(−5c)

=4$a^{2}$+6ab−10ac+6ab+9$b^{2}$−15bc−10ac−15bc+25$c^{2}$

=4$a^{2}$+12ab−20ac+9$b^{2}$−30bc+25$c^{2}$