Question

solve the following 2x+3/3+x=3/2 ​

Answer 1

$\huge\boxed{\fcolorbox{red}{lime}{verified\;answer\;✓}}$

$hey \: mate \\ here \: is \: your \: answer \\ \\ \frac{2x + 3}{3 + x} = \frac{3}{2} \\ \\ 2(2x + 3) = 3(3 + x) \\ \\ 4x + 6 = 9 + 3x \\ \\ = 4x - 3x = 9 - 6 \\ \\ x = 3 \\ \\ putting \: the \: value \: of \: x \: in \: that \\ fraction \\ \\ \frac{2(3) + 3}{3 + 3} = \frac{3}{2} \\ \\ \frac{6 + 3}{3 + 3} = \frac{3}{2} \\ \\ \frac{9}{6} = \frac{3}{2} \\ \\ hope \: its \: helpful \: to \: you$

Answer 2

Answer:

$\sf{\dfrac{2x+3}{3+x}=\dfrac{3}{2}}$

By cross multiplication,

$\longrightarrow{\sf{2(2x+3)=3(3+x)}}$

$\longrightarrow{\sf{4x+6=9+3x}}$

$\longrightarrow{\sf{4x-3x=9-6}}$

$\longrightarrow\underline{\sf{x=3}}$

$\:$

$\therefore{\sf{The\:value\:of\:x\:is\:\bf{3}}}$