solve the following 2x+3y=42
Answers
1 + 4 = 5
2 + 5 = 2 + 2(5) = 12
3 + 6 = 3 + 3(6) = 21
5 + 8 = 5 + 5(8) = 45
ALGORITHM: A + A(B) = C
ANSWER = 45
1 + 4 = 1 + 4 + (0) = 5
2 + 5 = 2 + 5 + (5) = 12
3 + 6 = 3 + 6 + (12) = 21
5 + 8 = 5 + 8 + (21) = 34
ALGORITHM: A + B + C' = C, where C' is the previous answer
ANS = 34
1 + 4 = 5 = 5
2 + 5 = (5 + 2) + (5) = 12
3 + 6 = (7 + 2) + (12) = 21
5 + 8 = (9 + 2) + (21) = 32
ALGORITHM: for {X=5, C = X + C' , X = X+2 };, where C' is the previous answer. A and B not used in equation,
ANS = 32
1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
5 + 8 = 13 (base 3) = 111
ALGORITHM: for {X=6, C = (A + B)^(10 -> X), X -1} (First answer in Base6, then Base 5, then 4, etc..)
ANS = 111
1 + 4 = 5
2 + 5 = 7 (base 5) =12
3 + 6 = 9 (base 4) = 21
4 + 7 = 11 (base 3) = 102
5 + 8 = 13 (base 2) (aka binary) = 1101
ALGORITHM: for {X=6, C = (A + B)^(10 -> X), X -1} (First answer in Base6, then
Base 5, then 4, etc...including "missing" numbers
ANS = 1101