Question

Solve the following (3/4)x^2-x-1=0

Answer 1

Answer:

$\mathcal{\purple{answer = \: x = 2 \: or \: x = \frac{ - 2}{3} }}$

$= ( \frac{3}{4} ) {x}^{2} - x - 1 = 0$

$= \frac{3 {x}^{2} }{4} - x - 1 = 0$

$= 3 {x}^{2} - 4x - 4 = 0$

$= 3 {x}^{2} - 6x + 2x - 4 = 0$

$= 3x(x - 2) + 2(x - 2) = 0$

$x - 2 = 0 \: or \: 3x + 2 = 0$

$\boxed{x = 2 \: or \: x = \frac{ - 2}{3} }$

$<marquee>{hope it HELPS you}</marquee>$