Question

solve the following 3^x=7^x-2​

Answer 1

Answer:

$x = \frac{1}{3},2$

Step-by-step explanation:

   $3x^{2} = 7x - 2$

⇒ $3x^{2} - 7x + 2 = 0$

We can write $-7x$ as $-6x-x$

⇒ $3x^{2} - 6x - x + 2 = 0$

⇒ $3x(x-2)-1(x-2)= 0$

⇒ $(3x-1)(x-2)=0$

⇒ $x = \frac{1}{3},2$