Question

solve the following​

Answer 1

Step-by-step explanation:

here is your answer

hOpe it's right

Answer 2

$\rm{ii)} \: \: \frac{x}{2} - \frac{3x}{4} + \frac{x}{6} = \frac{ - 2}{3} \\ \\ \tt= > \frac{6x - 9x + 2x}{12} = \frac{ - 2}{3} \\ \\ \tt = > 3 \{ - x\} = (- 2)12 \\ \tt = > \cancel - 3x = \cancel- 24 \\ \\ \tt = > \frac{\cancel3x}{\cancel3} = \frac{24}{3} \\ \\ \tt = > x = \green8$

And,

$\rm{v)} \: \frac{2x - 3}{5x - 4} = \frac{2x + 1}{5x + 20} \\ \\ \bf = > (2x - 3)(5x + 20) = (2x + 1)(5x - 4) \\ \bf = > \cancel{ {10x}^{2}} + 40x - 15x - 60 = \cancel{ {10x}^{2}} - 8x + 5x - 4 \\ \bf = > 40x - 15x + 8x - 5x = - 4 + 60 \\ \bf = > 48x - 20x = 60 - 4 \\ \bf = > \: \: 28x = 56 \\ \\ \bf = > \: \: \frac{28x}{28} = \frac{56}{28} \\ \\ \bf = > \: \: \: \: \: x = \green2$