Question

Solve the following:
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Answer 1

was trying very hard to ignore you. but couldn't :(

Answer:

57

Step-by-step explanation:

Using observations below:

• Numbers within a squared value is always be positive,
• Sum of 3 positive numbers that give 0 are 0, 0 and 0 (duh)

Therefore,

${(a + b - 5)}^{2} = 0$

Which means,

a+b = 5,

Using same relation (or whatever you wanna call it),

b+2c = -3

c + 3a = 10,

Solve these set of equations,

(That's the least you can do)

and you will get,

a=4

b= 1

and c = -2

Now,

${a}^{3} + {b}^{3} + {c}^{3} \\ = 64 + 1 - 8 \\ = 57$

See it was that easy.

Best of luck for the next ones.