Question

SOLVE THE FOLLOWING ​

Answer 1

Step-by-step explanation:

Dear Student,

Please find below the solution to the asked query :

x2−2(a+2)x + (a+1)(a+3) = 0We have, A = 1; B = −2(a+2); C = (a+1)(a+3)Now, D = B2−4AC=4(a+2)2 − 4(a+1)(a+3)=4[a2+4+4a−a2−4a−3]D=4 > 0Now, by quadratic formula, x = −B+D√2A and x = −B−D√2A⇒x = 2(a+2)+22 and x = 2(a+2)−22⇒x = a+3 and x = a+1

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