Question

solve the following:

Answer 1

Step-by-step explanation:

1 ∆ABC~∆ DAC

angle A =angle B given

line BC=BC common

line AB=Line AC

therefore ∆ABC~∆DAC

line AD = line bd cpct -1

2 line ab = line bd so

ab = 5cm

applying the formule of

h^2= B^2+p^2

5^2-4^2=p^2

25-16 = p^2

√9=p

p= 3 cm

3 area of ∆ adc

4+5+3/2

12/2= 6 so s=6

√s(s-a)(s-b)(s-c)

√6(6-5)(6-4)(6-3)

√6*1*2*3

√2*3*1*2*3

so 2*3=6 so area of triangle abc = 6

please mark me brailiest and follow and like it