Question

solve the following
3x-4/3x+3=2​

Answer 1

-8/3

Step-by-step explanation:

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$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\dfrac{3x - 4}{3x + 3} = 2$

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Bringing 2 into fraction form

$\implies{ \dfrac{3x - 4}{3x + 3} = \dfrac{2}{1} }$

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Cross multiplying

$\implies{1(3x - 4) = 2(3x + 2)}$

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Multiplying whole by 1 in LHS and by 2 in RHS.

$\implies{3x - 4 = 6x + 4}$

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Subtracting 3x and 6x in LHS and adding 4 and in RHS

$\implies{3x - 6x = 4 + 4}$

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It can be written as

$\implies{ - 3x = 8}$

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Now dividing

$\implies x = - \dfrac{8}{3}.$

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Hence, solved!✓

Answer 2

${\huge{\boxed{\red{Answer}}}}$

$\frac{3x - 4}{3x + 3} = \frac{2}{1} \\1(3x - 4) = 2(3x + 3) \\ 3x - 4 = 6x + 6 \\ 3x - 6x = 6 + 4 \\ - 3x = 10 \\ x = - \frac{10}{3} \\ x = - 3.3 </p><p>$