Question

solve the following 3x2+10x-80​

Answer 1

Answer:

\begin{gathered}3 {x}^{2} - 10x + 8 = 0 \\ 3 {x}^{2} - 6x - 4x + 8 = 0 \\ 3x(x - 2) - 4(x - 2) \\ (3x - 4)(x - 2) \\ x = 4 \div 3 \: and \: 2\end{gathered}

3x

2

−10x+8=0

3x

2

−6x−4x+8=0

3x(x−2)−4(x−2)

(3x−4)(x−2)

x=4÷3and2