Question

Solve the following
4
4 xy dx + (x² + 1) dy
=0​

Answer 1

Answer:

4xy dx + (x^2+1)dy = 0

x^2+1) dy = - 4xy dx

1/2x *(x^2+1) dx = -2ydy

2*ln|x| *(x^2+1)^2 dx = -y^2+c

y^2 + 2*ln|x|*(x^2+1)^2= c

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