Math, asked by garvita2794, 1 month ago

Solve the following

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Answered by mohit762161
0

Answer:

 {a}^{2}  +  {b}^{2}  \\  =  {( \frac{1}{7 - 4 \sqrt{3} }) }^{2}  +  { (\frac{1}{7 + 4 \sqrt{3} }) }^{2}  \\  = ( \frac{1}{49  +  16 \times 3})  + ( \frac{1}{49+ 16 \times  {3} } ) \\  =  \frac{1}{49 + 48}  +  \frac{1}{49 + 48}  \\  =  \frac{1}{97}  +  \frac{1}{97}  \\  =  \frac{2}{97}

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