Math, asked by gillnpmanjitpav6ty, 11 months ago

solve the following

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Answered by tushaar5
1
[tex]({a +b +c })^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + \: bc + \: av)[/text]

(6)^2 = a^2+ b^2+ c^2 + 2(11)


36= a^2+ b^2+ c^2 + 22

a^2+b^2+c^2=14





(a+b +c)^3=(a+b+c)(a^2+b^2+c^2 -ac -ba -ab)

(6) (14 -(11))
6× 3
18
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