Solve the following
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Answered by
1
Answer:
<x=55
<y=45
<z=70
Step-by-step explanation:
ABD is an isosceles triangle where AB is parallel to AD and
<B=<D
55=x
55=55
same happens with the BDC triangle where BC is parallel to DC and
<B=<D
y=45
45=45
In triangle ABD
55+55+<Z=180(the sum of angles of a triangle equals 180)
110+<Z=180
<Z=180-110
<Z=70
Answered by
1
Answer:
angle X = 55°
angle Y = 45°
angle Z = 70°
angle ABC=100°
Step-by-step explanation:
In ∆ABD:-
AB=AD, BC=DC (given)
so ∆ABD and ∆BCD are isosceles triangles
therefore angle ABD = angle X and similarly angle CDB = angle Y
(angles to equal sides of isosceles triangle are equal)
angle X = 55°
angle Y = 45°
sum of angle of triangle is 180°
in ∆ABD:-
angle Z = 180°-(angle B + angle X)
=> 180°-(55°+55°)=70°
angle Z = 70°
angle ABC= angle Y + angle ABD
=>45°+55°=100°
cheese
:)
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