Question

solve the following

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Answer 1

Solution:

We have to determine the equivalent resistance in the circuit.

We can observe that the resistances 8 Ω and 24 Ω are in parallel combination.

Let the equivalent resistances be Rₛ

Therefore:

→ 1/Rₛ = 1/8 + 1/24

→ 1/Rₛ = (3 + 1)/24

→ 1/Rₛ = 4/24

→ 1/Rₛ = 1/6

→ Rₛ = 6 Ω

Now the resistance 6 Ω is in series with 6 Ω

So, the equivalent resistance will be:

→ Equivalent resistance = (6 + 6) Ω

→ Equivalent resistance = 12 Ω

Which is our required answer.

Answer:

• The equivalent resistance in the circuit is 12 Ω

Additional Information:

Let R₁, R₂ and R₃ be resistors connected in series. Let Rₛ be the equivalent resistance of the circuit.

Then:

→ Rₛ = R₁ + R₂ + R₃

If they were connected in parallel combination, then:

→ 1/Rₛ = 1/R₁ + 1/R₂ + 1/R₃

The SI unit of resistance is ohm. It is denoted by the Greek letter Ω (Omega)