Question

solve the following


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Answer 1

Answer:

Correct option is C)

R

1

+R

2

R

1

R

2

=6Ω

Apply hit and trial method:

Take R

1

=1Ω;

1+R

2

R

2

=6Ω

R

2

=−5Ω (Not possible)

Take R

1

=5Ω;

5+R

2

5R

2

=6Ω

R

2

=−30Ω (Not possible)

Take R

1

=8Ω;

8+R

2

8R

2

=6Ω

R

2

=6Ω (Possible value of resistance)

Take R

1

=4Ω;

4+R

2

4R

2

=6Ω

R

2

=−4Ω (Not possible)

So, R

1

=8Ω is a possible value of resistance.