Question

Solve the following
5^1+x + 5^1-x = 10

Answer 1

5(¹+x) +5(¹-x) = 10

It is this question please confirm.....

Answer 2

${5}^{1 + x} + {5}^{1 - x} = 10$

${5}^{(1 + x)(1 - x)} = 10$

${5}^{1 + {x}^{2} } = 10$

${5}^{1 + {x}^{2} } = 5 \times 2$

${5}^{1 + {x}^{2} } \div 5 = 2$

${5}^{ 1 + {x}^{2} - 1} = 2$

${5}^{ {x}^{2} } = 2$

$log_{5}(2) = {x}^{2}$