solve the following
5-3√14/7+2√14
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2
Answer:
5−3
14
)/(7+2
14
)
Let us rationalize the denominator, we get
(5−3
14
)/(7+2
14
)=[(5–3
14
)(7–2
14
)]/[(7+2
14
)(7–2
14
)]
=[5(7–2
14
)–3
14
(7–2
14
)]/[72–(2
14
)2]
=[35–10
14
–21
14
+6.14]/[49–4.14]
=[35–31
14
+84]/[49–56]
=[119–31
14
]/[−7]
=−[119–31
14
]/7
=[31
14
–119]/7
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