Solve the following ?!!
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Answers
Answered by
0
⇒Jyoti
′
s way
Area of pentagon =2×
2
1
×(sum of parallel sides)×(Distance between them)
Area of pentagon =2×
2
1
×(15+30)×
2
15
=337.5 sq. metre
⇒Kavita
′
s way
Area of pentagon=Area of triangle + Area of rectangle
Area of pentagon =(
2
1
×15×15)+(15×15)=337.5 sq. metre
Answered by
0
Step-by-step explanation:
Area =
337.5
m
2
First way : By Jyoti's diagram,
Area of pentagon = Area of trapezium ABCP + Area of trapezium AECP
=
1
2
(
A
P
+
B
C
)
×
C
P
+
1
2
(
E
D
+
A
P
)
×
D
P
=
1
2
(
30
+
15
)
×
C
P
+
1
2
(
15
+
30
)
×
D
P
=
1
2
(
30
+
15
)
(
C
P
+
D
P
)
=
1
2
×
45
×
C
D
=
1
2
×
45
×
15
=
337.5
m
5
Second way : By Kavita's diagram
Here, a perpendicular AM has to be drawn to BE
AM = 30 - 15 = 15 m
Area of pentagon = Area of
Δ
ABE + Area of square B C D E
=
1
2
×
15
×
15
+
15
×
15
=
112.5
+
225.0
=
337.5
m
2
Hence total area of the pentagon shaped park =
337.5
m
2
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