Solve the following:
6(2x+3)-3(x-2)=6
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Given :-
6(2x+3)-3(x-2)=6
To find :-
The solution for the equation.
Solution :-
Given equation is 6(2x+3)-3(x-2)=6
=> (6×2x)+(6×3)-(3×x)-(3×-2) = 6
=> 12x+18-3x+6 = 6
=> (12x-3x)+(18+6) = 6
=> 9x+24 = 6
=> 9x = 6-24
=> 9x = -18
=> x = -18/9
=> x = -2
Therefore, The value of x = -2
Answer :-
The solution for the given equation is -2
Check :-
If x = -2 then LHS of the equation 6(2x+3)-3(x-2) becomes
= 6[(2×-2)+3]-3(-2-2)
= 6(-4+3)-3(-4)
= 6(-1)+12
= -6+12
= 12-6
= 6
= RHS
Therefore, LHS = RHS is true for x = -2
Verified the given relations in the given problem.
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