Question

Solve the following
60-litre solution of alcohol and water contains 20 litres of alcohol. How much alcohol must be Added
to produce a solution of 50% alcohol?

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Answer 1

Answer:

60 litre solution of alcohol and water.

in which alcohol quantity is 20 litre.

to produce a solution of 50% alcohol.

50% of 60

50/100 × 60

1/2×60

30 litre.

to produce a solution of 30 litre we have to add 30 litre - 20 litre = 10 litre.

10 LITRE IS YOUR ANSWER.

Answer 2

$\large \bold{ \underline{ \underline{ \: Answer : \: \: \: }}}$

$\to$ 20 litre of alcohol

$\large \bold{ \underline{ \underline{ \: Explaination: \: \: \: }}}$

Given ,

Total solution = 60 litre

Alcohol in solution = 20 litre

Let ,

x litre alcohol must be added to produce 50 % alcohol

Then , alcohol in solution at last equal to ( x + 20) litre

Total solution at last = (60 + x) litre

Alcohol at last is equal to 50% of total solution

$\to$ x + 20 = 50(60 + x)/100

$\to$ x + 20 = (60 + x)/2

$\to$ x + 20 = 30 + x/2

$\to$ x - x/2 = 30 - 20

$\to$ (2x - x)/2 = 10

$\to$ x/2 = 10

$\to$ x = 10 × 2

$\to$ x = 20

$\therefore$ 20 litre of alcohol must be added in 60 litre solution to get 50 % alcohol in the solution