Question

SOLVE THE FOLLOWING.

Answer 1

Answer:

(logx-loge)/x-e As loge=1

Dividing denominator by e

1/e{log(x/e)/( x/e-1)}

1/e{log(1+(x/e-1))/(x/e-1)}. Adding and subtracting 1 in log function

Using log(1+x)/x=1 when x approaches 0

1/e{1)=1/e