Question

Solve
the
following
​

Answer 1

Solution By RKRAUSHAN


$d = {b}^{2} - 4ac \\ \\ d = 64 - 4 \times 1 \times 6$

$d = 64 - 24 \\ \\ d = 40$

$x = \frac{ - b + \sqrt{d} }{2a} \\ \\ x = \frac{ - 8 \: + 2 \sqrt{10} }{2}$

x = -4 + √10

$similarly \: other \\ \: root \: become \: = > - 4 - \sqrt{10}$

$let \: \alpha = - 4 + \sqrt{10}$

$and \: \beta = - 4 - \sqrt{10}$

Further solution in attachment