Question

solve the following=(a)2x=17/9 (b) 74+x=63x (c) 92x=24+31x (d) 81y=32+4y​

Answer 1

Step-by-step explanation:

$a) \: 2x = \frac{17}{9} \\ = > x = \frac{17}{9} \times \frac{1}{2} = \frac{17}{18}$

$b) \: 74 + x = 63x \\ = > 62x = 74 \\ = > x = \frac{74}{62} = \frac{37}{31}$

$c) \: 92x = 24 + 31x \\ = > 61x = 24 \\ = > x = \frac{24}{61}$

$d) \: 81y = 32 + 4y \\ = > 77y = 32 \\ = > y = \frac{32}{77}$

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Answer 2

ANSWER:

a) 2x=17/9

x=17/9*2

x=17/18

b) 74x=63x

74=63x-x

74=62x

x= 74/62

x=37/31

c) 92x=24+31x

92x-31x=24

61x=24

x=24/61

d) 81y= 32+4y

81y-4y= 32

77y= 32

y= 32/77

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