solve the following (a _4b) ^3+(a+4b)^3
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={(a-4b)+(a+4b)}{(a-4b)^2 +(a+4b)^2 - 2(a-4b)(a+4b)
=(a-4b+a+4b)(a^2 +16b^2 -8ab+ a^2 +16b^2 +8ab - 2a^2 +4ab -4ab -16b^2)
=2a(a^2 +a^2 -2a^2)
=2a(2a^2-2a^2)
=2a(0)
=0
=(a-4b+a+4b)(a^2 +16b^2 -8ab+ a^2 +16b^2 +8ab - 2a^2 +4ab -4ab -16b^2)
=2a(a^2 +a^2 -2a^2)
=2a(2a^2-2a^2)
=2a(0)
=0
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