solve the following
a(a-1)-b(b-1)
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Hey mate!!!!
a(a - 1) - b(b - 1)
= a² - a - b² - b
arranging them
= a² - b² - a - b
= (a + b)(a -b) - a - b
[using the identity a² - b² = (a+b)(a - b) ]
=> (a + b)(a - b) - (a + b)
Hope it helps dear friend ☺️✌️✌️✌️
a(a - 1) - b(b - 1)
= a² - a - b² - b
arranging them
= a² - b² - a - b
= (a + b)(a -b) - a - b
[using the identity a² - b² = (a+b)(a - b) ]
=> (a + b)(a - b) - (a + b)
Hope it helps dear friend ☺️✌️✌️✌️
Imrat:
thank you
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one question more you solve it
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if root √2= 1.4114 then find the value of root √2-1 upon √2+1
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