solve the following: (a+c)x - (a-c)y = 2ab ; (a+b)x -(a-b)x = 2ab
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(a+c)x − (a−c)y = 2ab ....(1)
(a+b)x − (a−b)y = 2ab ..(2)
Adding (1) and (2), we get,
(a+c+a+b)x − (a−c+a−b)y = 4ab
⇒(2a+b+c)x − (2a−b−c)y = 4ab
⇒(2a+b+c)x + (b+c−2a)y = 4ab ...(3)
Subtracting (2) from (1), we get
(c−b)x + (c−b)y = 0
⇒(c−b)(x+y) = 0
⇒x + y = 0
⇒y = − x ...(4)
putting the value of y in (3), we get
(2a+b+c)x + (b+c−2a)(−x) = 4ab
⇒[(2a+b+c) −(b+c−2a)]x = 4ab
⇒(2a+b+c−b−c+2a)x = 4ab
⇒4ax = 4ab
⇒x = b
Now, from (4), we get
y = −b
so, x = b and y = − b is the solution.
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