solve the following
a) (x + 3) / (x - 2) = 7/2
b) (3x + 2) / (3x - 2) = 6
Answers
Answered by
1
Answer:
Given, 3(x+2)−2(x−1)=7
⇒3x+6−2x+2=7
⇒x+8=7
Subtract 8 on both sides,
x+8−8=7−8
⇒x=−1
Answered by
1
Answer:
Given: f(x)=3x2−7x−6
Which is of the from ax2+bx+c
⇒a=3,b=−7,c=−6
Now, α+β=−ab=3−(−7)
α+β=37....(1)
and αβ=ac=3−6
αβ=−2...(2)
(1) α2+β2=(α+β)2−2α+β
=(37)2−2(−2) [ from (1) & (2)]$$
=949+4=949+36=985
α2β2=(αβ)2=(−2)2=4
The pohynomical whose roots are α
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