Question

solve the following
a²-4a-5​

Answer 1

Step-by-step explanation:

${a}^{2} - 4a - 5 = 0 \\ {a}^{2} - 5a + a - 5 = 0 \\ a(a - 5) + 1(a - 5) = 0 \\ (a - 5)(a + 1) = 0 \\ a - 5 = 0 \: \: or \: \: \: a + 1 = 0 \\ a = 5 \: \: \: or \: \: \: a = - 1$