Math, asked by nitadhumal457, 7 months ago

.Solve the following activities : ( Marks : 4 ) i. []ABCD is trapezium, AB II CD , AM perpendicular to DC , AB= x , BC = (x-2) ,AM= (x-4), DC=(2x+1) and its area is 33 cm2. Find the lengths of all sides of the []ABCD. (Using information draw diagram) Solution: []ABCD is a trapezium. AB II CD A([]ABCD)= 1/2 (AB+CD) * ................ .................= (3x+1) * .............. 3x2 + .......... - 70 = 0 3x(...........)+10(..........)=0 (3x+10) (..........)=0 (3x+10)=0 or ............ = 0 x = - 10/3 or x = .......... But length is never negative. x not equal to -10/3 x = ...... AB = ..........., CD = ........... , AD=BC = .................​

Answers

Answered by pikly
0

Answer:

sorry i don't no the answer

Answered by omk40522
0

Answer:

AB∥CD

Area of a trapezium =

2

1

× (sum of parallel sides) × (height)

=

2

1

×(x+2x+1)(x−4)

=

2

1

(3x+1)(x−4)

=

2

3x

2

−12x+x−4

=

2

3x

2

−11x−4

Given the area of trapezium is 33cm

2

3x

2

−11x−4=66

⇒3x

2

−11x−70=0

⇒3x

2

−21x+10x−70=0

⇒3x(x−7)+10(x−7)=0

⇒(3x+10)(x−7)=0

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